In this problem, we will train a multi-class perceptron on data of the form (f(x) \in \mathbb{r}^2, y \in \{a, b, c\})(f(x)∈r 2 ,y∈{a, b,c}). in particular, we will use training data to update three weight vectors, w_y \in \mathbb{r}^2, y = a, b, cw y ∈r 2 ,y=a, b,c. we begin with the following set of randomly-initialized weight vectors: yy w_{y,1}w y,1 w_{y,2}w y,2 a -0.82 -0.02 b -1.63 -0.88 c 0.39 0.65

step-by-step :

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .