A30 kilogram mass is attached to a spring. if the frequency of simple harmonic motion is 2/π cycles/s, what is the spring constant k? k = correct: your answer is correct. n/m what is the frequency of simple harmonic motion if the original mass is replaced with an 120 kilogram mass? incorrect: your answer is incorrect. cycles/s

The spring constant k is N/m.

The frequency if the original mass is replaced with an 120 kilogram mass is cycles/s.

Step-by-step explanation:

From the information given:

and we want to find the spring constant k.

We can use this equation

, where

that describe simple harmonic motion.

The general solution of this equation is:

From this equation, the frequency of motion, is the number of cycles completed every one second, where is the period of motion and is  called the circular frequency of the system.

Thus,

(a) We know the frequency cycles/s and the mass kg, so we can solve the above equation for k the spring constant.

N/m

(b) To find the frequency of simple harmonic motion if the original mass is replaced with an 120 kilogram mass you must use the value of the spring constant that we found in (a) and this equation,

The frequency is cycles/s.

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

a

step-by-step explanation: