Three dogs eat 30 pounds of food in 10 days. if each dog eats the same amount, how much food does 1 dog eat in 1 day? 1 pound 3 pounds 9 pounds 10 pounds

1 dog eats 1 pound per day

Step-by-step explanation:

Step 1: Calculate amount eaten by 3 dogs in one day

This can be expressed as;

Total amount eaten=Amount eaten by 3 dogs in a day×number of days

where;

Total amount eaten=30 pounds

Amount eaten by 3 dogs in a day=a

Number of days=10 days

replacing;

30=(a×10)

10 a=30

a=30/10

a=3 pounds

The 3 dogs eat 3 pounds per day

Step 2: Calculate how much a dog eats in a day

Total amount eaten=amount eaten per dog×number of dogs

where;

Total amount eaten=3 pounds per day

amount eaten per dog=d

number of dogs=3

replacing;

3=d×3

d=3/3

d=1 pound per day

1 dog eats 1 pound per day

a

c

e

are your answers

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this