The distribution of the diameters of a particular variety of oranges is approximately normal with a standard deviation of 0.3 inch. how does the diameter of an orange at the 67th percentile compare with the mean diameter?

is the required relation of the diameter of an orange at the 67th percentile compare with the mean diameter.        

Step-by-step explanation:

We are given the following information in the question:

Standard Deviation, σ = 0.3 inch

We are given that the distribution of  diameters is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.67.

Calculation the value from standard normal z table, we have,  

which is the required relation of the diameter of an orange at the 67th percentile compare with the mean diameter.

side xy = 10

sin(x) = 4/5

cos(x) = 3/5

tan(x) = 4/3

step-by-step explanation:

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)