Line with a slope of 0 that passes through the point (6,-11)

We want to find a line with a slope of 0 that passes through the point (6, -11).

The line is:

y = -11

First, a general line is something of the form:

y = a*x + b

Where a is the slope and b is the y-intercept.

If the slope is equal to 0, then the line becomes:

y = b

Now we want this line to pass through the point (6, - 11)

Notice that the line is an horizontal line of constant y-value, so if we want this line to pass through that point, then the line must be:

y = -11

This is the line we wanted to get.

If you want to learn more, you can read:

link

The equation of a line with a slope of 0 that passes through the point (6,-11) will be y = - 11

Step-by-step explanation:

We want to determine the equation of a line with a slope of 0 that passes through the point (6,-11)

Slope of the line = change in the value of y on the vertical axis / change in the value of x on the x axis.

Recall,

The the equation of a straight line is represented in the slope intercept form is

y = mx + c

Where

m = slope

c = intercept on the y axis

From the equation information given,

slope, m = 0

y = -11

x = 6

To get the intercept, c,

y = mx + c

-11 = 0 × x + c

-11 = c

c = -11

The equation of a line with a slope of 0 that passes through the point (6,-11) will be

y = 0x - 11

y = - 11

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150

sorry not sure

step-by-step explanation: