Solve the following system of equations:

x + 3y = −4
x + 5y = −6

a) (1,1)
b) (-1,1)
c) (1,-1)
d) (-1,-1)

D) (-1,-1)

Step-by-step explanation:

Given that:

x + 3y = −4   eq1

x + 5y = −6 eq2

Subtracting eq1 from eq2 we get:

2y = -2

Dividing both sides by 2 we get:

y = -1

Put value of y in eq1

x + 3(-1) = -4

x - 3 = -4

x = -4 + 3

x = -1

so the solution set is (-1,-1)

i hope it will help you!

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

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step-by-step explanation:

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