![\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x+1}{2}~~,~~\cfrac{y-1}{2} \right)~~=~~\stackrel{M}{(3~~,~~1)}\implies \begin{cases} \cfrac{x+1}{2}=3\\[1em] x+1=6\\ \boxed{x=5}\\[-0.5em] \hrulefill\\ \cfrac{y-1}{2}=1\\[1em] y-1=2\\ \boxed{y=3} \end{cases}](/tpl/images/0375/1448/af121.png)
The midpoint of line
ab
is m(3, 1). if the coordinates of a are (1, -1), what are the co...
Mathematics, 15.11.2019 02:31 collin0123
The midpoint of line
ab
is m(3, 1). if the coordinates of a are (1, -1), what are the coordinates of b?
Answers: 1
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