The manager of a white-tailed deer population surveyed the population 2 years in a row, counting the number of females. (note: often in wildlife management, only females are tracked.) she counted 196 last year and 232 this year. if the deer population grows geometrically and continues to grow at this rate, what will be the size of the population of female deer 5 years from now? (hint: do two separate calculations to answer the question.)

539

Step-by-step explanation:

The geometric growth equation is given by :-

, where is the initial population , r is the multiplicative rate of growth and t is the time.

Given : The manager of a white-tailed deer population surveyed the population 2 years in a row, counting the number of females.

She counted 196 last year and 232 this year.

Multiplicative rate of growth=

For now, the population = .

Then , the function to expression the population after t years is given by :-

Now , for t= 5, the population after 5 years will be :-

Hence, the size of the population of female deer 5 years from now= 539

what? ?

what type of question is thiss

step-by-step explanation:

find the magnitude of the trig term  

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find the upper bound of the range.

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step-by-step explanation: