The average diameter of sand dollars on a certain island is 5.00 centimeters with a standard deviation of 0.90 centimeters. if 16 sand dollars are chosen at random for a collection, find the probability that the average diameter of those sand dollars is more than 4.73 centimeters. assume that the variable is normally distributed.

the probability that the average diameter of those sand dollars is more than 4.73 centimeters is 0.5910

Step-by-step explanation:

Given information:

mean, x = 5

standard deviation, σ = 0.9

number of sample, n = 16

now we calculate the probability that the average diameter of those sand dollars is more than 4.73 centimeters.

P(x>4.73)  = P (z > (4.73 - x) / (σ )

                = P (z > (4.73 - 4) / (0.9 )

                = P (z > 0.203)

                = 0.5910

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