Manco went scuba diving. as he dove deeper, the water pressure around him increased at a constant rate.
the table compares manco's depth (in meters) and the water pressure around him in atmospheres).
pressure (atmospheres)
2.3
depth (meters)
13
17
21
2.7
3.1
what was the pressure around manco when he was 30 meters deep?
atmospheres

4.0 atmospheres

Step-by-step explanation:

As the depth(meters) increases so does the Pressure (atmospheres) look at the chart to help you get a clear understanding:

Depth(meters) Pressure(atmospheres)

14 2.4

15 2.5

16 2.6

17 2.7

18 2.8

19 2.9

20 3.0

21 3.1

22 3.2

23 3.3

24 3.4

25 3.5

26. 3.6

27 3.7

28 3.8

29 3.9

30 4.0

Step-by-step explanation:

This problem is solves using sequences. The right table about Depth and Pressure is:

Depth (m)   Pressure (atm)

     13                 2.3

     17                 2.7

     21                 3.1

If you look closely, you will find that the sequence with given data is +4 for Depth, and +0.4 for Pressure. Also, we can generalize and say that the sequence could be +1 for Depth and +0.1 for Pressure, if we use one by one sequence, 13, 14, 15, 16, 17, ..., until 30.

If we continue the table with the first sequence, we have:

Depth   Pressure

  25          3.5

  29          3.9

  33          4.3

So, if we use now the second sequence, we will find that 30 meters Depth belongs to 4.0 atmospheres Pressure, because if we sum +1 to Depth, we have to sum +0.1 to Pressure to maintain the proper sequence.

Therefore, the answer is 4.0 atmosphere.

ye

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: