Ahot air balloon is tethered to the ground by rope that is 200 feet long. the balloon floats into the sky at a rate of 4 feet per second. the equation y=4x gives the height, y, of the balloon x seconds after leaving the ground.

graph the function
what’s the domain?
what’s the range?
interpret the x and y intercepts.

Step-by-step explanation:

y is the height of the balloon.  x is the time in seconds.

The balloon starts on the ground, so the smallest value of y is 0.  We know the rope is 200 feet long, so the biggest value of y is 200.  So the range is 0 ≤ y ≤ 200.

Find the value of x at each end of the range.

When y = 0:

0 = 4x

x = 0

When y = 200:

200 = 4x

x = 50

So the domain is 0 ≤ x ≤ 50.

The x and y-intercept is (0, 0).  This means the balloon is initially on the ground.

Graph: desmos.com/calculator/eaavtvbuxm

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).