Which shows one way to determine the factors of x3 – 12x2 – 2x + 24 by grouping?

The question is

Shows the factor of x³-12x²-2x+24 by grouping method.

Now,

take ' x² ' common from first two terms and ' -2 ' from the last two terms.

x³-12x²-2x+24

=x²(x-12)-2(x-12)

=(x-12)(x²-2) are factors.

(x-12)(x^2-2)

Step-by-step explanation:

Factor the polynomial by grouping

We group first two terms and last two terms

Now we factor out GCF from each group

GCF of x^3 -12x^2 is x^2

GCF of -2x+24 is -2

(x-12)(x^2-2)

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3