Bob and alice have 35 pumpkin pies altogether. bob and catherine have 55 pumpkin pies all together. if catherine has three times as many pumpkin pies as alice, how many pumpkin pies does alice have

Alice has 10 pumpkin pies.

Step-by-step explanation:

Given, Bob and Alice has 35 pumpkin pies and Bob and Catherine has 55 pumpkin pies. Let, Bob has x pumpkin pies and Alice has y pumpkin pies. Also given that, Catherine has three times as many as pumpkin pies as Alice. That's why let Catherine has 3y pumpkin pies. Now, make this conditions into an equation.

x + y = 35(i)

or, x + 3y = 55(ii)

By solving these equation number i and ii, we get,

2y = 20

y = 10.

So, Alice has 10 pumpkin pies.

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

.25

step-by-step explanation: