The sum of three positive integers is 18 and their product is 210. if the smallest of the integers is 5, what are the remaining two integers.

The remaining numbers are 7 and 6.

Step-by-step explanation:

Given:

The sum of three positive integers =18

Their product is 210.  

The smallest of the integers is 5

To find:

The other two integers=?

Solution:

Let the other two numbers be a, b

Now,

sum of three numbers = 18

sum of two numbers + 5 = 18

a + b = 18 – 5

a + b = 13 (1)

And, product of 3 numbers = 210

a x b x 5 = 210

a x b = 42(2)

Now, as a and b are positive integers a and b values should be lesser than 13 and greater than 5 as given that 5 is the smallest of 3 numbers.

so a x b = 42

a x b = 7 x 6  

So, by comparison a = 7 and b = 6.  

Let us check it with equation (1)

7 + 6 = 13

13 = 13  

Hence, the remaining numbers are 7 and 6.

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

step-by-step explanation:

why? because i noticed a pattern. 60 120. those numbers without the zero, make the 6 times tables leaving your answer to be b since 6 times 4 is 24 and adding a zero making it 240.