Suppose an airplane climbs 15 feet for every 40 feet it moves forward. what is the slope of this airplane's ascent?
a) -3/8
b) -8/3
c) 1/3
d) 3/8

3/8

Step-by-step explanation:

slope= 15 /40 =3/8

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

1,8,15,22,29,36,43,50

step-by-step explanation: