The company ships the components in lots of 200. lots containing more than 20 defective components may be returned. find a 95% confidence interval for the proportion of lots that will be returned. use the normal approximation to compute this proportion. round the answers to four decimal places. the 95% confidence interval is

[ 0.0584, 1.0416 ]

Step-by-step explanation:

Data provided in the question:

sample size, n = 200

Number of defective components = 20

thus,

p = = 0.1

Now,

Confidence interval for p is given as:

⇒ p ±

here, z = 1.96 for 95% confidence interval

therefore,

⇒ 0.1 ±

or

⇒ 0.1 ± 0.0416

or

confidence interval = [ 0.1 - 0.0416, 0.1 + 0.0416 ]

or

confidence interval = [ 0.0584, 1.0416 ]

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.

f is the midpoint of