Acompany produces a women's bowling ball that is supposed to weigh exactly 14 pounds. unfortunately, the company has a problem with the variability of the weight. in a sample of 11 of the bowling balls the sample standard deviation was found to be 0.71 pounds. construct a 95% confidence interval for the variance of the bowling ball weight. assume normality.

Step-by-step explanation:

Given : A company produces a women's bowling ball that is supposed to weigh exactly 14 pounds.

Sample size : n=11

Degree of freedom =n-1=10

Sample standard deviation : s= 0.71 pounds

Significance level for 95% confidence interval :

We assume that the bowling ball weight is normally distributed.

Using chi-square distribution table, the required critical values are :-

Then, the 95% confidence interval for the variance of the bowling ball weight will be :

∴ The 95% confidence interval for the variance of the bowling ball weight will be :

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

30

step-by-step explanation:

times by times