Two rectangular properties share a common side. lot a is 33 feet wide and 42 feet long.

the combined area of the lots is 1,848 square feet. how many feet wide is lot b? show work!
(a) 11 feet
(b) 14 feet
(c) 44 feet
(d) 56 feet

The width of lot B is 11 feet, so option A is correct.

Step-by-step explanation:

Given:

To find:

How many feet wide is Lot B?  

Solution:

we know that, area of a rectangle is length x breadth

Then area of lot A = 33 x 42 = 1386 square feet.

And area of lot B = width x 42

Now, we are given that, total area = 1848  

area of lot A + area of lot B = 1848  

1386 + width x 42 = 1848  

width x 42 = 1848 – 1386  

width x 42 = 462  

width = 11

Hence, the width of lot B is 11 feet, so option A is correct.

one of each metals

step-by-step explanation:

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

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