To how many patrons could a telephone company furnish numbers having five digits, the first digit not being zero? i know the answer is 90,000 im just wondering how to do it

90,000

Step-by-step explanation:

Given

A Company has to provide 5-digit numbers(The first digit≠0)

This question can be solved with Permutations and Combinations

Assume there are 5 blank spaces representing any phone number

The first digit can be filled in 9 ways(excluding 0 ={1,2,3,4,5,6,7,8,9})

The second digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

The third digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

The fourth digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

The fifth digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

So total number of ways to fill the 5 blanks

⇒Total number of 5-digit phone numbers= 90000

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

what? ?

what type of question is thiss

step-by-step explanation: