1pt
choose two of the following choices that can represent the nth term of the sequence: 54, 18, 6, 2,

a_n=162\cdot3^n\ ,\ \ n\ge1
a
n

=162⋅3
n
, n≥1

a_n=54\cdot3^{n-1}\ ,\ \ n\ge1
a
n

=54⋅3
n−1
, n≥1

a_n=54\cdot\frac{1}{3}^{n-1}\ ,\ \ n\ge1
a
n

=54⋅
3
1


n−1
, n≥1

a_n=54\cdot3^n\ ,\ \ n\ge1
a
n

=54⋅3
n
, n≥1

a_n=162\cdot\frac{1}{3}^n\ ,\ \ n\ge1
a
n

=162⋅
3
1


n
, n≥1

is this part of a question or something

i think the answer is b.

step-by-step explanation:

not 100% sure though.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~