in the figure, pbx and qby are segments and angle pab = angle qab.
prove that pqxy is cyclic.

Since and by inscribed angle theorem,

By transitivity,

This follows from the converse of the theorem that angles subtended on a circle by a chord of fixed length are equal. Here, chord $PQ$ of the circle passing through $PQXY$ subtends equal angles at points $X$ and $Y$ on the circle.

1     3    

step-by-step explanation:

hopefully im right

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0