On one side of a balancing scale there are 5 blocks: 3 weighing 3 grams each and 2 weighing x each. the scale is balanced if 8 blocks weighing x grams each are placed on the other side of the scale. how many does each side of the unknown blocks weigh

The weight of unknown block  on each side of the scale is 1.5 grams.

Step-by-step explanation:

The number of blocks on 1 side  = 5 blocks

Now, 3 blocks  = 3 grams each

⇒Total weight of 3 blocks  = (3 grams )times  3  = 9 grams

    2 blocks  = x grams each

⇒Total weight of 2 blocks  = (x grams ) 2  = 2 x grams

So the total weight on 1 side  = weight of 5 blocks combined

= 9 grams + 2x  grams = (9 + 2x) grams

The total weight on other side of scale =  8  blocks times (x grams)

= (8x) grams

Now, The SCALE IS BALANCED if :

(9 + 2x) grams  =  (8x) grams

or, 9 + 2x = 8x

⇒9 = 8x - 2x = 6x

or, x  = 9/6 = 1.5

⇒ x = 1.5 grams

Hence, the weight of unknown block  on each side of the scale is

1.5 grams, so that the scale is balanced.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )