The height (in inches) of men at uh is assumed to have a normal distribution with a standard deviation of 3.6 inches. the height (in inches) of women at uh is also assumed to have a normal distribution with a standard deviation of 2.9 inches. a random sample of 49 men and 38 women yielded respective means of 68.3 inches and 64.6 inches. find the 90% confidence interval for the difference in the heights of men at uh and women at uh

The required 90% confidence interval would be (2.55,4.85).

Step-by-step explanation:

Since we have given that

Standard deviation of men = 3.6 inches

Standard deviation of women = 2.9 inches

Average of men = 68.3 inches

Average of women = 64.6 inches

Number of men = 49

Number of women = 38

α = 0.10

So, the confidence interval would be

Hence, the required 90% confidence interval would be (2.55,4.85).

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.