Find the altitude of an isosceles triangle with base 16 and congruent sides of length 9.

the altitude is 12.04 units

Step-by-step explanation:

An isosceles triangle is a triangle which has two equal sides and two equal angles. The diagram of the isosceles triangle is shown in the attached diagram. The two equal sides are 9 units each. The isosceles triangle ABC forms two right angle triangle ACF and BCF. The base AB is 16 units.

We want to determine the altitude, CF. We will apply Pythagoras theorem

Hypotenuse^2 = opposite^2 + adjacent ^2

Hypotenuse = 9

Adjacent = 16/2 = 8

Opposite = CF

9^2 = 8^2 + CF^2

CF^2 = 81 + 64 = 145

CF = √145 = 12.04

answer: x=60

answer:

the answer is b) divide by -4 on each side and flip the sign.

step-by-step explanation:

we first need to start by dividing. this is because it is a multiplication problem to start.

we also need to make sure we flip the sign because any time you multiply or divide by negative numbers, the sign must be flipped.