An experiment consists of choosing an urn with the following probabilities that urn 1, urn 2, or urn 3 will be chosen: 1/2, 1/4, and 1/4, respectively. urn 1 contains 15 brown marbles and 14 clear marbles. urn 2 contains 6 brown marbles, 11 clear marbles and 9 red marbles. urn 3 contains 7 brown marbles, 8 clear marbles and 5 red marbles.

a marble is then chosen from the chosen urn. what is the probability that urn 3 was chosen, given that the marble chosen was clear?

a) 0.1000

b) 0.4000

c) 0.1333

d) 0.3063

e) 0.2236

option E

Step-by-step explanation:

let E₁ be the event of urn 1

let E₂ be the event of urn 2

let E₃ be the event of urn 3

P(E₁) =

P(E₂) =

P(E₃) =

Let A be the probability of getting clear marble

P(A/E₁) = =0.483

P(A/E₂) = = 0.423

P(A/E₃) = =  0.4

required probability

P(E₃/A) =

P(A) = P(E₁)P(A/E₁) + P(E₂)P(A/E₂) +P(E₃)P(A/E₃)

P(A) = 0.5 x 0.483  + 0.25 x 0.423 +0.25 x 0.4

P(A) = 0.447

now,

P(E₃/A) =

P(E₃/A) = 0.2147

hence, the correct answer is option E

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step-by-step explanation:

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step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00