Astudy of a company's practice regarding the payment of invoices revealed that an invoice was paid an average of 20 days after it was received. the standard deviation equaled five days. assuming that the distribution is normal, what percent of the invoices were paid within 15 days of receipt? multiple choice
a. 15.87%
b. 37.91%
c. 34.13%
d. 86.74%

=0.1587 or 15.87%

So option A is correct answer so 15.87% of the invoices were paid within 15 days of receipt.

Step-by-step explanation:

In order to find the percent of the invoices paid within 5 days of receipt we have to find the value of Z first.

where:

X is the random varable which in our case is 15 days

u is the mean or average value which is 20 days

S is the standard deviation which is 5 days

Z=-1.0

We have to find Probability at Z less than -1

P(Z<-1.0) which can be written as:

=1-P(Z>1.0)

From Cumulative distribution table:

=1-(0.3413+0.5)

=0.1587 or 15.87%

So option A is correct answer so 15.87% of the invoices were paid within 15 days of receipt.

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

120 seems like the most sensible answer.

step-by-step explanation:

if there is only one topping on all caramel apples and there's 120 of them. then all apples should/will be covered in sprinkles. make sense?