Which equation describes this line?
(1.13)
(-2.4)
o a. y-1 = 3(x - 13)
o b. y= 2 = 3(x-4)
o c. y - 4 = 3 (x - 2)
o d . y - 4 = 3(x + 2)

The equation of line with given points is  y - 4 = 3 ( x + 2 ) .

Step-by-step explanation:

Given as :

The points of line are ( 1 , 13 )   and    ( - 2 , 4 )

The point slope intercept equation of line is

y - = m ( x -   )

Where m is the slope of line

So , Slope , m =

Or, m =  

Or, m =  

∴    m = 3

Now The equation of line is

y - = m ( x -   )

Or. y - 13 = 3 ( x -  1 )

Or, y - 13 = 3 x - 3

Or, y = 3 x - 3 + 13

∴   y = 3 x + 10

I.e y - 4 = 3 x + 6

Or, y - 4 = 3 ( x + 2 )

Hence The equation of line with given points is  y - 4 = 3 ( x + 2 ) . Answer

b. astronomers

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !