Im failing jancita buys 4 pounds of turkey and 2 pounds of ham. she pays a total of 30$ and the turkey costs 1.50$ less per pound than ham. what would be the combined cost of 1 pound of turkey and 1 pound of ham.

The combined cost of 1 pound of turkey and 1 pound of ham is $10.50

Step-by-step explanation:

Consider the provided information.

Let x represents the cost of turkey  (per pound)

Let y represents the cost of ham (per pound)

4 pounds of turkey and 2 pounds of ham. She pays a total of 30$

The turkey costs 1.50$ less per pound than ham.

Substitute the value of x in

Now substitute the value of x in

Hence, the cost of  1 pound of turkey is $4.50  and 1 pound of ham costs    $6.00 .

Therefore the cost of 1 pound each is:

$4.50+$6=$10.50

The combined cost of 1 pound of turkey and 1 pound of ham is $10.50

The combined cost is $10.50.

Step-by-step explanation:

Let the cost of 1 pound of ham be 'x'.

Let the cost of 1 pound of turkey be 'x-1.50'.

Number of pounds of hams purchased = 2

Number of pounds of turkey purchased = 4

Total amount paid = $30.

According to question, it becomes

So, cost of 1 pound of turkey would be

So, combined cost of 1 pound of turkey and 1 pound of ham is given by

Hence, the combined cost is $10.50.

46.2+112.3

step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.