Solve the system.
y= 3x2−2x+3
y = x + 3

the solutions are and

(0,3) and (1,4)

Step-by-step explanation:

Given that:

y= 3x2−2x+3   eq1

y = x + 3   eq2

Putting value from eq2 to eq1

x + 3 = 3x2−2x+3

3x2−2x+3  - x - 3 = 0

3x2−3x = 0

Taking 3 common

x2 - x = 0

x(x-1)= 0

So

x = 0      and   x = 1

Now put value in eq2

y = 0 + 3   and    y= 1 + 3

y = 3 and y = 4

So solution sets are:

(0,3) and (1,4)

i hope it will help you!

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: