Which equation represents a circle with the same radius as the circle shown but with a center at (-1, 1)? (x – 1)2 + (y + 1)2 = 16 (x – 1)2 + (y + 1)2 = 4 (x + 1)2 + (y –1)2 = 4 (x + 1)2 + (y – 1)2 = 16

Last option:

Step-by-step explanation:

The center-radius form of the circle equation is:

Where the center of the circle is at the poitn  and "r" is the radius.

You can identify from the figure attached that the radius of the circle shown is 4 units.

Since the other circle has the same radius and its center is at the point ; you can identify that:

Therefore, substituting values into , you get that the equation of that circle is:

Step-by-step explanation:

According to the Center-Radius Formula, [H, K] represents the centre of the circle, where the negative symbols give the OPPOSITE terms of what they really are, and the radius is ALWAYS squared. So, with the centre of plus your radius of 4, you have this:

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the answer is true.

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2