Find the equation in slope- intercept from that describes a line through (4,-2) slope-3

The answer is: y = -3x + 10

Step-by-step explanation:

Given point: (4, -2)

Given slope: m = -3

Use the point slope form of the equation and substitute:

y - y1 = m(x - x1)

y - (-2) = -3(x - 4)

y + 2 = -3x + 12

y = -3x + 10

Proof:

f(4) = -3(4) + 10

f(4) = -12 + 10

= -2, giving the point (4, -2)

Hope this helps! Have an Awesome Day!! :-)

the solution is h=10 because you add 9 to each side of the equation.