If an object is dropped from a height of 96ft, the function h(t) = -62 + 96 gives the height of the object after t seconds. when will the object hit the ground?

Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.

Therefore the equation  h(t) = 80t – 16t2 becomes 0= 80t – 16t2

Solving the equation for t gives  80t =16t2 or 16t=80 or t=5sec

The object hits the ground 5 seconds after it is launched.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.