According to zimmels (1983), the sizes of particles used in sedimentation experiments often have a uniform distribution. in sedimentation involving mixtures of particles of various sizes, the larger particles hinder the movements of the smaller ones. thus, it is important to study both the mean and the variance of particle sizes. suppose that spherical particles have diameters that are uniformly distributed between .01 and .05 centimeters. find the mean and variance of the volumes of these particles. (recall that the volume of a sphere is (4/3)πr 3 .)

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )