Wyatt’s eye-level height is 120 ft above sea level, and shawn’s eye-level height is 270 ft above sea level. how much farther can shawn see to the horizon? use the formula d = square root of 3h/2, h> 0 with d being the distance they can see in miles and h being their eye-level height in feet.

Let

d-------> is the distance they can see in miles

h-------> is the eye-level height in feet

we know that

The formula to find the distance d is equal to

Step

Find the distance d for Wyatt’s eye-level

Step

Find the distance d for Shawn’s eye-level

Step

Subtract the distance d for Shawn’s eye-level from the distance d for Wyatt’s eye-level

therefore

the answer is

Shawn can see farther

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.