According to the department of transportation, 27% of domestic flights were delayed in 2007 at jfk airport. five flights are randomly selected at jfk.

what is the probability that all five flights are on time? a) 0.2073b) 0.7927c) 0.8487d) 0.1513

a) 0.2073

Step-by-step explanation:

Binomial distribution formula  :

,

where n= total number of trials.

x= number of successes.

p= probability of getting success in each trial.

q= 1-p =  probability of getting failure in each trial.

For the given question , let the flight are on time be success.

Let x denote the number of flight are on time .

Given : Proportion of domestic flights were delayed in 2007 at JFK airport : q=0.27

Proportion of domestic flights were on time in 2007 at JFK airport :

p=1-0.27=0.73

Five flights are randomly selected at JFK.

i.e. n=5

Now, the probability that all five flights are on time will be :-

Hence, the probability that all five flights are on time = 0.2073

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew