Solve the following integrals. (a) x x2+1 dx = + c (b) 4 e− x dx 0 = (c) 1 5 4−x2 dx 0 = (d) x 5−x dx} = + c (e) 8 1 x+x1/3 dx 1 = (f) sec2(7x) tan4(7x) dx = + c (g) 5 25 − x2 dx 0 = (h) 5 x − 2 dx 0 = (i) 4 x2 − 6x + 8 dx 0 = (j) cos3(y) sin2(y) dy = + c (k) given that 3 f(x) dx 1 = 7, 11 f(x) dx 3 = 13, and 11 f(x) dx 9 = 6, then 3 xf(x2) + 3f(x) + 5 dx 1 =