For males the expected pulse rate is 70 per second and the standard deviation is 10 per second. for women the expected pulse rate is 77 per second and the standard deviation is 12 per second. let ! x ¼ the sample average pulse rate for a random sample of 40 men and let ! y ¼ the sample average pulse rate for a random sample of 36 women. what is the approximate distribution of \overline{x}-\overline{y} ? justify your answer.

Normal

Step-by-step explanation:

Given are the pulse rates average and std deviation for men and women.

MenWomenDifference

Pulse rate per second7077-7

Std dev per second1012  

Variance100144244

n4036  

Variance/n2.546.5

Std error  2.549509757

The first one represents X that of men and ii one that of women Y.

is Normal

Mean = difference in means

and Std dev of difference =

Thus using the above we calculate the distribution of difference of means is Normal with mean = -7 and std error = 2.5495

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

nswer: a   y-axis

step-by-step explanation: