1. tickets to a fundraiser are $14 if purchased ahead of time

araiser are $14 if purchased ahead of time, and $25 if purchased

door. the total amount raised from all ticket sales was $788. if the number

on tickets purchased ahead of time was five less than the number of tickets that

were purchased at the door, how many tickets were purchased at the door

22 tickets

Step-by-step explanation:

Let the number of ticket purchased ahead of time be a and the number of tickets purchased at the door be d.

We know that purchasing ahead of time costs $14 while purchasing at the door costs $25. Writing this in equation form yields:

14a + 25d = 788i

Now we also know that ticket purchased ahead of time was 5 less than tickets purchased at the door. Hence,

a = d - 5ii

We can solve both equations simultaneously .Let's substitute ii into I

14( d -5) + 25d = 788

14d - 70 + 25d = 788

39d - 70 = 788

39d = 788 + 70

39d = 858

d = 858/39 = 22

We know a = d - 5

This mean a = 22 - 5 = 17

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24