Find the image vertices for a dilation with center (0,0)
and a scale factor of 4.

* show steps if you can. if not, it’s fine

Image vertices are : A' = (-12 , 4) ; B' = (16 , -12) ; C' = (8 , 12) ; D' = (-4 , 16)

Step-by-step explanation:

Given :

Scale Factor = 4

Vertices given in the above graph :

A = (-3 , 1) ; B = (4 , -3) ; C = (2 , 3) ; D = (-1 , 4)

Calculation :

To find the image vertices for a dilation with center (0 , 0) we have to multiply the vertices by scale factor 4.

So the image vertices are :

A' = (-12 , 4) ; B' = (16 , -12) ; C' = (8 , 12) ; D' = (-4 , 16)

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The resultant image vertices will be,

A' = (-12 ,4) ;  B' = (16 , -12) ; C' = (8, 12) and D'= (-4, 16)

Step-by-step explanation:

The co-ordinates of the given image vertices are,

A = (-3 , 1) ; B = (4 ,-3); C = (2, 3) and D = (-1, 4)

If the image is dilated with center (0, 0) and a scale factor of 4, then in the resultant image, all the co-ordinates will be multiplied by a factor of 4.

So, the resultant image vertices will be,

A' = (-12 ,4) ;  B' = (16 , -12) ; C' = (8, 12) and D'= (-4, 16)

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: