Acircular spinner is divided into 5 equal parts, if the spinners spun 3 times what is the probability that an even number is spun all 3 times?

When a spinner is divided into equal parts, each segment in the spinner has an equal probability. The probability that the outcomes of the 3 spin is even is 8/125

Let the numbers on the spinner be:

The even numbers are:

The probability of 1 even number is:

So, we have:

In three spin, the probability that all outcomes are even is:

Hence, the probability that the outcomes of the 3 spin is even is 8/125

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d. 8/125

Step-by-step explanation:

If each part is numbered from 1 to 5, then 2 of the parts are even (2 and 4).  So the probability of landing on an even number is 2/5.

The probability of landing on an even number 3 times is:

P = (2/5)^3

P = 8/125

dont think so

step-by-step explanation:

i'm pretty sure the answer is a. decreases with increase in