If f(x) = 6x + 3, find −1

a) f−1(x) = x−6/3

b) f−1(x) = 6x −3

c) f−1(x) = −3− 6x

d) f−1(x) = x−3/6

D

If you are to plot its graph, then:

y = 6x + 3

Now swap the x and y:

x = 6y + 3

y = (x - 3) / 6

im a goose

step-by-step explanation:

gg5

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)