Tanner and sheldon got receivers for christmas. if they leave at the same time, tanner walking north at 2.5 mph and sheldon is walking east at 3 mph, how long will they be able to talk to each other if the range of communication is 4 miles?

Assume that they start at the origin. After h hours, Tanner will be at point , while Sheldon will be at point

So, the distance between them is

This distance becomes 4 miles after

So, they can walk for a little bit more than 1 hour before they get out of range.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."