A(1, 1), b(3, 1), k=2 (x, y) (2x, 2y) a(1, 1)

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

step-by-step explanation:

im not sure what the answer is

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110