The piecewise function f(x) has opposite expressions.

f(x) = startlayout enlarged left-brace 1st row 1st column 2 x minus 1, 2nd column x less-than 0 2nd row 1st column 0, 2nd column x = 0 3rd row 1st column negative 2 x + 1, 2nd column x greater-than 0

which is the graph of f(x)?

on a coordinate plane, a piecewise function has 2 lines. the first line goes through (negative 3, 4) and goes down to a closed circle at (negative 1, 0). the second line has a closed circle at (1, 0) and goes up through (3, 4).

on a coordinate plane, a piecewise function has 2 lines. the first line goes up through (negative 3, negative 4) to a closed circle at (0, 2). the second line has a closed circle at (0, 2) and goes down through (3, negative 4).

on a coordinate plane, a piecewise function has 2 lines. the first line goes up from (negative 2, negative 5) to a closed circle at (0, negative 1). the second line has a closed circle at (0, 1) and goes down through (2, negative 3).

on a coordinate plane, a piecewise function has 2 lines. the first line goes down through (negative 1, 3) to a closed circle at (0, 1). the second line has a closed circle at (0, negative 1) and goes up through (2, 3).

On a coordinate plane, a piecewise function has 2 lines. The first line goes up from (negative 2, negative 5) to a closed circle at (0, -1). The second line has a closed circle at (0, 1) and goes down through (2, -3).

Step-by-step explanation:

Let's visualize this piecewise function, or function by parts.

Piecewise function is a function where each piece of function describes a behavior, i.e. returning another value depending on the input value.

Piecewise functions are pretty useful when we study limits.

According to the description given, the 3rd. option matches the graph. The second behavior (0,0) we'll describe it as a point.

C or the third graph

Step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

the correct answers i think are b. and d.

give me brainliest if it is correct!