For the following three problems (1. – suppose the scores on an exam in a large class are normally distributed with a mean μ = 81 points (out of 100), and standard deviation σ = 5 points. the instructor decides to set the "failing" score at 70, so anyone who scored below a 70 has a failing score. what proportion of exams will have failing scores? show all work, use provided standard normal table (z table), and show the proportion as a decimal rounded to four decimal places.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry

wait nvm i know the correct answer now its 100%   81 square feet

~batmans wife dun dun