P(4,-6), y= -3

write an equation of the line that passes through point p and is perpendicular to the line with the given question.

The equation of the line that passes through point P(4,-6) and is perpendicular to the line y = -3 is x = 4

The slope-intercept form of the equation of a line is:

y  =  mx  +  c

where m is the slope

c is the y-intercept

The equation of the given line is:

y  =  -3

Comparing y = -3 with y = mx + c

The slope, m = 0

This means that, y = -3 is a vertical line

Any line that is perpendicular to y = -3 will be a perpendicular line

Since the perpendicular line passes through the point P(4, -6), the equation of the perpendicular line is:

x   =  4

Learn more here: link

me! what did you put for this question?

step-by-step explanation: