What additional information will prove abc=cde by hl?

If CE = AE , then ΔABE ≅ ΔC D E by H L theorem.

Step-by-step explanation:

H L THEOREM:

If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.

Here, in ΔABE and ΔC D E

Given, ∠ABE  = ∠CDE    (90°)

Now, for H L theorem,

the Hypotenuse of the given triangle ΔABE  =  AE

Hypotenuse of the given triangle ΔCDE  =  CE

Now, if CE = AE

Δ ABE ≅ Δ CDE

Hence, if CE = AE , then ΔABE ≅ ΔC D E by H L theorem.

idk

step-by-step explanation:

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