Can anyone solve this step by step its 3x-2y=5 3x+y=8 in substitution they are both the same problem

3x-2y=5

3x+y=8

Rewrite the second equation as y = -3x +8

Substitute that into the first equation for y:

3x-2(-3x+8) = 5

Use distributive property:

3x +6x -16 = 5

Combine like terms:

9x - 16 = 5

Add 16 to both sides:

9x = 21

Divide both sides by 9:

x = 21/9

x = 7/3

Replace X in the first equation and solve for y:

3(7/3) -2y = 5

7 - 2y = 5

Subtract 7 from both sides:

-2y = -2

Divide both sides by -2:

y = 1

The solution is (7/3, 1)

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step-by-step explanation:

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong