Pls me< 3
1. the solution to the system of equations below is no solution.

8x-4y=-8
y=2x-5

(a)use the substitution method to justify that the given system of equations has no solution.

(b) what do you know about the two lines in this system of equations?

a)8x-4(2x-5)= -8

b) parallel lines(they never touch)

and for A all you have to do is solve it like normal and you will end up with a impossible solution

Step-by-step explanation:

A first for be we must substitute y in the 1st equation for 2x-5

then you distribute 8x - 4(2x-5) = -8

8x - 8x + 20 = -8

x values cancel out and your left with 20 = - 8

B this tells you that there is no solution

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)