Which statements are true about the ordered pair (5, −6) and the system of equations? {x+y=−1 3x−y=21 select each correct answer. the ordered pair (5, −6) is a solution to the first equation because it makes the first equation true. the ordered pair (5, −6) is a solution to the second equation because it makes the second equation true. the ordered pair (5, −6) is not a solution to the system because it makes at least one of the equations false. the ordered pair (5, −6) is a solution to the system because it makes both equations true.

The ordered pair (5,-6) is a solution to the first equation because it makes the first equation true.

The ordered pair (5,-6) is a solution to the second equation because it makes the second equation true.

Step-by-step explanation:

The given system of equations are :

In ordered pair (5, −6) , x -coordinate =5 and y-coordinate = -6

Put x= 5 and y=-6 in (i) , we get

, which is true.

That means (5,-6) is a solution to the first equation because it makes the first equation true.

Put x= 5 and y=-6 in (ii) , we get

, which is true.

That means (5,-6) is a solution to the second equation because it makes the second equation true.

So , the correct statements are :

The ordered pair (5,-6) is a solution to the first equation because it makes the first equation true.The ordered pair (5,-6) is a solution to the second equation because it makes the second equation true.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12